Question

A gas exerts a pressure of 1.8 atm at a temperature of 60 degrees celsius. What is the new temperature when the pressure of the gas changes to 4 atm?

Answer 1

The answer for the following problem is mentioned below.

• Therefore the final temperature of the gas is 740 K

Step-by-step explanation:

Given:

Initial pressure of the gas (
`P_(1)`) = 1.8 atm

Final pressure of the gas (
`P_(2)`) = 4 atm

Initial temperature of the gas (
`T_(1)`) = 60°C = 60 + 273 = 333 K

To solve:

Final temperature of the gas (
`T_(2)`)

We know;

From the ideal gas equation;

we know;

P × V = n × R × T

So;

we can tell from the above equation;

P ∝ T

(i.e.)

`(P)/(T)` = constant

`(P_(1) )/(P_(2) )` =
`(T_(1) )/(T_(2) )`

Where;

`P_(1)` = initial pressure of a gas

`P_(2)` = final pressure of a gas

`T_(1)` = initial temperature of a gas

`T_(2)` = final temperature of a gas

`(1.8)/(4)` =
`(333)/(T_(2) )`

`T_(2)` =
`(333*4)/(1.8)`

`T_(2)` = 740 K

Therefore the final temperature of the gas is 740 K