Question

objects one and to attract each other with an electrostatic force of 36 units if the charge of object one is halved then the new electrostatic force will be

Answer 1

The new electrostatic force will be half the initial force.

Step-by-step explanation:

Let is call the charges of the two objects
`Q_1` and
`Q_2`, if the separation between them is
`R`, then the electrostatic force
`F` between them will be

`F = k(Q_1Q_2)/(R^2),`

where
`k` is the coulomb's constant.

If let's say the charge
`Q_1` is halved, then it becomes
`Q_1/2`. The electrostatic force then becomes

`F_(new) = k((Q_1/2)Q_2)/(R^2) = k(Q_1Q_2)/(2R^2),`

`\boxed{F_(new) =(F)/(2).}`

Thus, the new electrostatic force will be half the initial force.