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Factor completely (X^2 + x - 6) (2x^2 + 4x) =
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3 votes
Factor completely
(X^2 + x - 6) (2x^2 + 4x) =

User Nicola Uetz
by
3.6k points

1 Answer

6 votes

Answer:

= 2x^4 + 6x^3 - 8x^2 + 24x

= 2x ( 2x^3 + 3x^2 - 4x + 12)

Explanation:

(X^2 + x - 6) (2x^2 + 4x) =

Let's open the brackets carefully

x^2 * 2x^2 + x^2*4x + x*2x^2 + x*4x - 6*2x^2 - 24x

= 2x^4 + 4x^3 + 2x^3 + 4x^2 - 12x + 24x

= 2x^4 + 6x^3 - 8x^2 + 24x

= 2x ( 2x^3 + 3x^2 - 4x + 12)

User Cespon
by
3.1k points
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