Question

What is the factored form of x6 - 9?

O (x + 3)(x - 3)
O (x^5 + 3)(x – 3)
O (x^3+ 3)(x^2 – 3)
O (x^3 + 3)(x^3 - 3)​

Answer 1

D

Explanation:

`x^(6)` - 9 ← is a difference of squares and factors in general as

a² - b² = (a + b)(a - b)

Given

`x^(6)` - 9

= (x³ )² - 3²

= (x³ + 3)(x³ - 3) → D