Question

A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 . If the charge is 0.030 m from the source of the electric field, what is the electric potential energy of the charge?

Answer 1

0.027 J

Explanation:

The formula of the potential energy in electrostatic (U) is

`U = q * E * d`

The values given in the question are

Charge : q =
`4.5 * 10^(-5) C`

Electric Field strength : E =
`2.0 * 10^(4) N/C`

Distance : d is 0.030 m

Insert in the formula , will give us

`U = 4.5 * 10^(-5) C * 2.0 * 10^(4) N/C * 0.030 m`

Further solving it

`U = 0.027 J`

Which is the required answer.

Thanks