121k views
3 votes
The loudness, L, of a sound (measured in decibels, dB) is inversely proportional to the square of the distance, d, from the source of the sound. A person 15 feet from a jetski, it is 95 decibels loud. How loud is the jetski when a person is 48 feet away?

1 Answer

3 votes

Answer:

Jet ski is 29.688 db Loud when a person is 48 feet away.

Explanation:

Given:


L
\frac1d

Distance of a person from Jet ski = 15 feet

Loudness of the sound = 95 decibels

We need to find the Loudness when the distance of person is 48 feet away.

Solution:


L
\frac1d

so we get;


L=\frac kd

Where k ⇒ Constant.

first we will find value of k when
L=95\ db; d= 15\ ft

Substituting the values we get;


95=(k)/(15)\\\\k = 1425\ db.ft

Now we need to find
L when
d =48\ ft


L=\frac kd


L= (1425\ db.ft)/(48\ ft) = 29.688\ db

Hence Jet ski is 29.688 db Loud when a person is 48 feet away.

User Levenshtein
by
7.6k points