Question

LiOH + KCI → LiCl + KOH

a) I began this reaction with 20.0 grams of LiOH. What is my theoretical yield of LiCI?​

Answer 1

To find the theoretical yield of LiCl, calculate the moles of LiOH and use stoichiometry to determine the moles of LiCl produced. Then convert moles to grams using the molar mass of LiCl. The theoretical yield of LiCl is 35.2 grams.

Step-by-step explanation:

The balanced equation provided is:

• LiOH + KCl → LiCl + KOH

To find the theoretical yield of LiCl, you need to calculate the moles of LiOH and use stoichiometry to determine the moles of LiCl produced. Here's how:

• 1. Calculate the moles of LiOH using its molar mass: 20.0 g / 23.95 g/mol = 0.835 mol

• 2. Use the stoichiometry of the balanced equation to determine the moles of LiCl: 0.835 mol LiOH * (1 mol LiCl / 1 mol LiOH) = 0.835 mol LiCl

• 3. Convert the moles of LiCl to grams using its molar mass: 0.835 mol LiCl * 42.39 g/mol = 35.395 g LiCl

Therefore, the theoretical yield of LiCl is 35.395 grams.

Answer 2

35.42g

Step-by-step explanation:

LiOH + KCI → LiCl + KOH

Let us determine the molar mass of LiOH and LiCl. This is illustrated below:

Molar Mass of LiOH = 7 + 16 + 1 = 24g/mol

Molar Mass of LiCl = 7 + 35.5 = 42.5g/mol.

Now, we can obtain the theoretical yield of LiCl as follow:

From the equation above,

24g of LiOH reacted to produce 42.5g of LiCl.

Therefore, 20g of LiOH will react to produce = (20 x 42.5)/24 = 35.42g of LiCl.

From the above calculations, the theoretical yield of LiCl is 35.42g