Given:
Volume of water in each container.
To find:
Difference in the rate of change.
Solution:
Take any two points on container 1.
Let the points are (10, 2) and (20, 4).
![$m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ej5dbt33a3msr0t53n100ov7xd8u2xicjg.png)
![$m=(4-2)/(20-10)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8vathx9efiijs5mi2t3h4kwqdkj600k0uf.png)
![$m=(2)/(10)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qspa8fqdn2jxjnypt0iwwsx6lw718ofgjb.png)
![$m=(1)/(5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/32s8m6qv12fe1uefbu69mgat8wn949haak.png)
Rate of change for container 1 is
.
Take any two points on container 2.
Let the points are (5, 2) and (10, 4).
![$m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ej5dbt33a3msr0t53n100ov7xd8u2xicjg.png)
![$m=(4-2)/(10-5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1qdt18iqds6i09zgdqa4lcf6ymdj5i43og.png)
![$m=(2)/(5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/nc6cobjvg91390angva1fd8z73u3r7lhff.png)
Rate of change for container 2 is
.
Difference =
![(2)/(5)-(1)/(5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/f3vy9lompsn8oofsqmudf6wjtqa0byj8u9.png)
![$=(1)/(5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/5gu5kgybk4ihsjgzv8wcqfre9xel3mv57l.png)
The difference in the rate of change between the two containers is
gallon per minute.