Answer:
0.856 L of H2 will be produced
Step-by-step explanation:
Step 1: Data given
Mass of zinc = 2.5 grams
Molar mass of zinc = 65.38 g/mol
Step 2: The balanced equation
Zn + 2HCl → ZnCl2 + H2
Step 3: Calculate moles Zn
Moles Zn = 2.5 grams .65.38 g/mol
Moles Zn = 0.0382 moles
Step 4: Calculate moles H2
For 1 mol Zn we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2
For 0.0382 moles Zn we'll have 0.0382 moles Zn
Step 5: Calculate volume of H2
1 mol = 22.4 L
0.0382 moles = 22.4 * 0.0382 = 0.856 L
0.856 L of H2 will be produced