Answer:
Step-by-step explanation:
Area of square loop = L²
Flux Φ = area x magnetic field
= L²B
Frequency = f
angular velocity ω = 2πf
a )
Let at time t = 0 , the magnetic field is making 90 degree with the face of the loop
flux through loop = L²B
After time t , coil will turn by angle ω t = 2πft
Flux through the loop = L²B cosω t
Φ (t) = L²B cosω t
= L²B cos2πft
b )
emf induced e
= - d/dt [Φ (t)]
= - d/dt [ L²B cosω t]
= L²B ω sinω t
= L²B 2πf sin2πft
c )
current = e / R
(L²B ω/ R ) sinω t
Power delivered
P(t) = VI ,
VOLT X CURRENT
= AB ω sinω t X ( AB ω/ R ) sinω t
= L⁴B² 4π²f²/R sin²2πft
e )
torque = MB sinω t
τ(t) = i(L²B ) sinω t
= (L²B ω/ R ) sinω t x (L²B ) sinω t
= (L²B )²ω/ R sin²ω t
= (L²B )² 2πf/ R sin²2πft