Solution and Explanation:
arrival time = 24 per minute, processing time = 12 minutes, number of servers = 1 ( work for 8 hours a days)
a. arrival rate = 60 divide 24 = 2.5 customer per hour, service rate = 60 divide 12 = 5 customers per hour
therefore, the probability that the operator will be busy = 2.5 divide 5 = 0.5
thus, the percentage of idle time = 1 minus 2.5 divide 5 = 0.50
Thus, the percenatge idle time is 50%
b. the average spent by a student waiting in a line =

= 0.20 hours.
Thus, on an average a student spent 0.20 hours waiting in line.
c. the average number in waiting line = 0.5 customers
d. the probability for the given condition to happen is 0.25, 25%