Question

Teresa is maintaining a camp fire. She can keep the fire

burning for 4 hours with 6 logs. She wants to know how
many logs (y) she needs to keep the fire burning for 18
hours. She assumes all logs are the same.
How many logs does Teresa need to maintain the fire
for 18 hours

Answer 1

27 logs that Teresa needs to maintain the fire

for 18 hours.

Solution given:

4 hours=6 logs

1 hours =6/4 =3/2 logs

now

18 hours=3/2*18=3*9=27 logs

so

value of y is 27 logs

Answer 2

27 logs

Explanation:

4hrs = 6 logs

18hrs= ?x

Then you cross multiply.

so,18x6= 4x

4x/4=108/4

x=27 logs

Answer 3

27 logs does Teresa need to maintain the fire

for 18 hours.

Solution given:

4 hours=6 logs

1 hours =6/4 =3/2 logs

now

18 hours=3/2*18=3*9=27 logs

so

value of y is 27 logs