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In a thundercloud there may be an electric

charge of 47 C near the top and −47 C near

the bottom. These charges are separated by

approximately 1.8 km.

What is the magnitude of the electric force

between them? The Coulomb constant is

8.98755 × 10^9 N · m^2

/C^2

.

Answer in units of N.

HELOOOOOOOOOOOOOOOOOOOOOOOOOOOO??!?!?!?!?!?!??!?!?!?!?!?

User Skinner
by
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1 Answer

6 votes

Answer:

u would use the formula for electrostatic force of attraction which is

F = q1q2 / 4pie r^2

Step-by-step explanation:

i think it would 47 and 47 =2209 ,divide by (4 × pie × 8.98755 × (1.8 ×(10 ^3) )^2)

User Esen
by
4.9k points