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What is the value of the discriminant of the quadratic equation -2^3=-8x+8

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the value of the discriminant of the quadratic equation
-2x^2=-8x+8 is
D =0 .

Explanation:

Here we need to find What is the value of the discriminant of the quadratic equation -2x^2=-8x+8 or ,
-2x^2=-8x+8 .

We know that for a quadratic equation ,
f(x) = ax^2+bx+c , Discriminant is :


D = b^2-4ac

Now , let's frame equation
-2x^2=-8x+8 in form of
f(x) = ax^2+bx+c :


-2x^2=-8x+8


2x^2-8x+8=0


x^2-4x+4=0

Comparing values we get that here , a=1 , b = -4 , c = 4 . Putting these values in
D = b^2-4ac :


D = (-4)^2-4(1)(4)


D =16-16


D =0

Therefore , the value of the discriminant of the quadratic equation
-2x^2=-8x+8 is
D =0 .

User Tekknolagi
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