Question

the second term in a sequence is 13. the term to term rule is "add 6". write an expression in terms of n, for the nth term of a sequence

Answer 1

`a_(n)` = 6n + 1

Explanation:

This is an arithmetic sequence with n th term

`a_(n)` = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = a₂ - 6 = 13 - 6 = 7 and d = 6, thus

`a_(n)` = 7 + 6(n - 1) = 7 + 6n - 6 = 6n + 1