The number of students in each van = 18
The number of students in each bus = 58
(x,y) = (18,58)
Explanation:
Let us assume the the number of students a van can carry = x
Let us assume the the number of students a bus can carry = y
At university A:
Total number of students = 752
Total number of vans = 16
So, total students carried by 16 vans = 16 x
The total number of buses = 8
So, total students carried by 8 buses = 8 y
⇒ 16 x + 8 y = 752
or, 2 x + y = 94 ... (1)
At university B:
Total number of students = 380
Total number of vans = 5
So, total students carried by 5 vans = 5 x
The total number of buses = 5
So, total students carried by 5 buses = 5 y
⇒ 5 x + 5 y = 380
or, x + y = 76 .... ... (2)
Now, solving (1) and (2) , we get:
2 x + y = 94
x + y = 76
(-) (- ) (-) ⇒ 2 x - x + y - y = 94 - 76
or, x = 18
Substituting in (2) , we get: y = 76 - 18 = 58 , or y = 58
So, the number of students in each van = 18
The number of students in each bus = 58
(x,y) = (18,58) is the ordered pair