Question

Which point is on the circle with center (-3,-1) that contains the point (1, 2)?

Answer 1

Any point that is 5 units from the center

Explanation:

The given circle is centered at;

(-3,-1) and contains (1,2).

The radius is given by:

`r = √((x_2-x_1)^2 +(y_2-y_1)^2)`

We substitute the point to get:

`r = √((1- - 3)^2 +(2- - 1)^2)`

`r = √(4^2 +3^2)`

`r = √(25) = 5`

Therefore any point that is 5 units from the center lies on this circle.