Question

It's in the attachment.
Thanks

Answer 1

1/3

Explanation:

Let
`(x)/(y) =(m)/(n) =(k)/(p) =t`

∴ x = yt , m = nt and k = pt

`(p*y*m)/(x*n*k) = (p*y*nt)/(yt *n*pt )=(t)/(t^2) = (1)/(t)`

∴ 1/t = 3

∴ t = 1/3

∴ x = (1/3) y ⇒ y = 3x

And n = 3m and p = 3k

∴
`(x+m+k)/(y+n+p) = (x+m+k)/(3x + 3m + 3k) = (x+m+k)/(3(x + m + k)) = (1)/(3)`