Question

A golf ball thrown at an angle of 20 relative to the ground at a speed of 40 m/s. if the range of the motion is 55m. what is the maximum height that the ball reaches

Answer 1

Maximum height reached is given as H = 5.00 m

Step-by-step explanation:

As we know that if the ball is projected at some angle with the horizontal then the range of the projectile is given by the formula

`R = (v^2 sin2\theta)/(g)`

here we have

`R = 55 m`

`\theta = 20^o`

v = 40 m/s

Now we have

`55 = (40^2 sin40)/(g)`

`g = 18.7 m/s^2`

now for maximum height we have

`H = (v^2sin^2\theta)/(2g)`

`H = (40^2 sin^220)/(2(18.7))`

`H = 5 m`