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41 votes
In the figure below, the segments IJ and IK are tangent to the circle centered at O. Given that OJ=8.4 and OI=15.9, find IK.

In the figure below, the segments IJ and IK are tangent to the circle centered at-example-1
User Daniel Antos
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1 Answer

22 votes
22 votes

Answer:

IK = 13.5

Explanation:

A^2 + B^2 = C^2

(8.4)^2 + B^2 = (15.9)^2

70.56 + B^2 = 252.81

B^2 = 182.25

B =13.49925... ≈ 13.5 = IK

User Kostix
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