Question

It's in the attachment
URGENT

Answer 1

Explanation:

`(2a)/(a + b - c) = (2b)/(b + c - a) = (2c)/(a + c - b) = k \\ \\ by \: theorem \: on \: equal \: ratios \\ \\ (2a + 2b + 2c)/(a + b - c + b + c - a + a + c - b) = k \\ \\ (2(a + b + c))/(a + b + c) = k \\ \\ \therefore \: k = 2`