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Calculate the mass of Cu(NO3)2.4H2O required to prepare 100.0 mL of 0.200 M solution.
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Calculate the mass of Cu(NO3)2.4H2O required to prepare 100.0 mL of 0.200 M solution.

User Stereoputrid
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1 Answer

1 vote

Answer:

8921.96g

Step-by-step explanation:

Molar mass of Cu (NO3)2.4H2O= 446.0982g/mol

Number of mole = concentrate × volume

n= 100×0.2=20

No of mole= mass/molar mass

Mass= 20×446.0982

Mass= 8921.96g

Mass = 8.9kg.

User Connexo
by
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