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4 votes
Solve the system of equations 3x + y = 3 and 7x + 2y = 1.

2 Answers

4 votes

Explanation:

3x+y = 3.........equation 1

7x+2y = 1.........equation 2

Multiplying equation 1 by 2 and Solving both

6x+2y = 6

7x+2y =1

- - -

-x = 5

Therefore x = -5

Putting x= -5 in equation 1

3 * -5 +y = 3

-15 + y = 3

y = 3+15

therefore y = 18

Hope it helped

User Lschin
by
6.7k points
6 votes

Answer:


x=-5\\y=18

Explanation:

Given equations:


3x + y = 3 Equation:1


7x + 2y = 1 Equation:2

Multiplying Equation:1 by '2'


6x+2y=6 Equation:3

Using elimination method:

Subtract Equation:3 from Equation:2:


7x+2y-(6x+2y)=1-6\\\\7x+2y-6x-2y=-5

Solving the like terms:


7x-6x=-5\\\\x=-5

Putting the value of 'x' in Equation:1


3x + y = 3


3(-5) + y = 3\\\\-15+y=3\\\\

Adding '15' both sides:


y=3+15\\\\y=18

The solution of the equations is:


x=-5\\y=18

User Helene
by
6.2k points
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