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Write the equation of a line that passes through the point (2,-1) and is parallel to the line y=-2/5x+3.

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Answer: y + 1 = 2/5(x - 2), or y = 2/5x - 9/5

Explanation:

for this you'll need point-slope form, which is:

y - y1 = m(x - x1)

m = slope

the slope is 2/5, because parallel lines have the same slope.

plug values in:

y - (-1) = 2/5(x - 2)

y + 1 = 2/5(x - 2)

if you want this in mx + b form:

y + 1 = 2/5(x - 2)

y + 1 = 2/5x - 4/5

y = 2/5x - 9/5

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