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Suppose that the loan amount on mortgages for a particular zip code is normally distributed with a mean of 154,449, measured in dollars, with a standard deviation of 14,794. What is the z value for a loan of 162,443 dollars? Answer to three decimal places if needed.

User Berzemus
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1 Answer

1 vote

Answer:

The z value for a loan of 162,443 dollars is 0.5404.

Explanation:

We are given that the loan amount on mortgages for a particular zip code is normally distributed with a mean of 154,449, measured in dollars, with a standard deviation of 14,794.

Let X = loan amount on mortgages for a particular zip code

So, X ~ N(
\mu=154,449,\sigma^(2)=14,794^(2))

Now, the z score probability distribution is given by;

Z =
(X-\mu)/(\sigma) ~ N(0,1)

where,
\mu = mean loan amount = $154,449


\sigma = standard deviation = $14,794

So, the z-score for a loan of 162,443 dollars is given by;

Z =
(162,443 - 154,449)/(14,794)

=
(7,994)/(14,794) = 0.5404

Therefore, the z value for a loan of 162,443 dollars is 0.5404.

User Boyko Perfanov
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