Question

A 3/8-16 UNC nut and bolt are used to assemble steel plates. The clearance holes in the plates are 7/16 in. The plates are clamped together by the nut and bolt with a force of 500 lb. If the torque coefficient is 0.22, determine the (a) torque that is applied and (b) resulting stress on the bolt

Answer 1

a) T=41.25 in-lb

b) Resulting stress=6493.5 lb/in^2

Step-by-step explanation:

a) The torque is:

`T=C*D*F`

where C is the torque coefficient, F the force and D is 3/8. Replacing:

`T=0.22*3/8*500=41.25 in-lb`

b) The area is:

`A=0.25\pi (D-(0.9743)/(n))^(2)=0.25\pi (3/8-(0.9743)/(16))^(2)=0.077 in^(2)`

The resulting stress is:

`Resulting stress=(F)/(A)=(500)/(0.077) =6493.5 lb/in^(2)`