Question

What temperature would be required to keep 0.895mol of gas in a 28.6L tank at a pressure of 0.500atm?

Answer 1

The temperature would be 194, 8 K.

Step-by-step explanation:

We use the formula:

PV=nRT --> T=PV/nR

T= 0,500 atm x 28, 6 L/ 0,895 mol x 0,082 l atm /K mol

T= 194,8494345 K