Answer:
The reaction quatient Q is 0.306
Step-by-step explanation:
Step 1: data given
Volume = 2.50 L
Temperature = 1100 K
Number of moles C = 6.75 moles
Number of moles H2O = 13.5 moles
Number of moles CO = 3.10 moles
Number of moles H2 = 9.00 moles
Step 2: The balanced equation
C(s)+H2O(g)⇌CO(g)+H2(g)
Step 3: Calculate the concentration
Concentration = moles / volume
[C] = 6.75 moles / 2.5 L
[C] = 2.7 M
[H20] = 13.5 moles / 2.5 L
[H2O] = 5.4 M
[CO] = 3.10 moles / 2.5 L
[CO] = 1.24 M
[H2] = 9.00 moles / 2.5 L
[H2]= 3.6 M
Step 4: Calculate Q
Q = [CO][H2] / [C][H2O]
Q = (1.24 * 3.6)/(2.7*5.4)
Q = 0.306
The reaction quatient Q is 0.306