Answer:
0.2665
Explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{(\pi(1-\pi))/(n)}](https://img.qammunity.org/2021/formulas/mathematics/college/fmbc52n1wcsstokpszqrr2jempwxl2no1b.png)
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
![n = 193, \pi = (42)/(193) = 0.2176](https://img.qammunity.org/2021/formulas/mathematics/college/kd3u5yilq2n2mppyunib33g1xcgm10mhfn.png)
90% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The upper boundary of this interval is:
![\pi + z\sqrt{(\pi(1-\pi))/(n)} = 0.2176 + 1.645\sqrt{(0.2176*0.7824)/(193)} = 0.2665](https://img.qammunity.org/2021/formulas/mathematics/college/6nra8iyrbun97fj2rwx3y6ko0svt7bxypt.png)
So the answer is 0.2665