Final answer:
The side length of the square base of the pyramid is 8 inches.
Step-by-step explanation:
A pyramid with a square base has a volume equal to the product of the base area and the height divided by 3. In this case, the volume is given as 128 cubic inches and the height is given as 6 inches. Let's denote the side length of the square base as s. We can set up the equation:
128 = (s^2)(6) / 3
Multiplying both sides by 3 and dividing by 6, we get:
s^2 = 64
Taking the square root of both sides, we find:
s = 8
Therefore, the side length of the square base of the pyramid is 8 inches.