Answer:
77% percent yield
Step-by-step explanation:
2 Al + 3 CuSO4 → Al2(SO4)3 + 3 Cu
(3.7 g Al) / (26.98154 g Al/mol) x (3 mol Cu / 2 mol Al) x (63.5463 g Cu/mol) = 13.07 g Cu in theory
(10 g) / (13.07) = 0.765 = 77% yield
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