Answer:
x = 5
y = 0
respectively
Explanation:
in order to solve this system of equation we say that let
0.4x - 0.1y = 2...............................................................equation 1
0.2x + 0.5y = 1 ...............................................................equation 2
from equation 2
0.2x + 0.5y = 1 ...............................................................equation 2
0.2x = 1 - 0.5y
divide both sides by the coefficient of x which is 0.2
0.2x/0.2 = ( 1- 0.5y)/0.2
x = ( 1- 0.5y)/0.2................................................ equation 3
substitute for equation 3 in equation 1
0.4x - 0.1y = 2...............................................................equation 1
0.4 ( 1 - 0.5y)/0.2 - 0.1y = 2
0.4 - 0.2y/0.2 - 0.1y = 2
multiply through by 0.2
we have,
0.4 - 0.2y - 0.02y = 0.4
collect the like terms
0.4 - 0.4 = 0.2y + 0.02y
0 = 0.22y
divide both sides by the coefficient of y which is 0.22
0/0.22 = 0.22y/0.22
y = 0
put y = 0 into equation 3
x = ( 1- 0.5y)/0.2................................................ equation 3
x = 1 - 0.5(0)/ 0.2
x = 1- 0/0.2
x = 1/0.2
x = 5
therefore the value of x is 5 and y is 0 respectively