Answer:
(a) 300 W
(b)0.90 J
Step-by-step explanation:
(a) The electric power for any circuit element is given as
![P=IV](https://img.qammunity.org/2021/formulas/physics/high-school/4ofuq13a657if0wubbuuhk1p7xuymrpvco.png)
Here I is current passing in the circuit and V is the voltage.
Given I = 12 A and V =25 V.
Substitute the given values, we get
![P=12 A *25 V](https://img.qammunity.org/2021/formulas/physics/high-school/1jo2pbev27jgjbuju7vweixd8j8rzic1tc.png)
P = 300 W.
Thus, the power defibrillator deliver to the body is 300 W.
(b) To calculate the electric energy use the relation between electric energy, power and time as
![E=Pt](https://img.qammunity.org/2021/formulas/physics/high-school/28kov6pbqhthc2e20ckgzmld9zv5fi9a45.png)
Given t = 3 ms.
Substitute the values, we get
![E=300 W* 3* 10^-^3s](https://img.qammunity.org/2021/formulas/physics/high-school/vjasftxhyydoniviov4tn56k8d6q1mh09u.png)
E = 0.90 J.
Thus, the energy transferred is 0.90 J.