Answer:
Explanation:
Some information in this question is missing as we are not given with the probability p that any weaving machine will break down anytime.
For solving this question, Suppose the probability p = 0.2
n = no. of machines
p = probability of breaking at any time and
x = the number of successes and
Let A be a random variable that denotes the number of weaving machines that will break down.
A follows binomial distribution with n = 8 and p = 0.2
We will use the formula P(A=x) = nCx *
*

Now, the probability that at any given time none of the weaving machines will be broken down:
P (A=0) = 8C0 *
*

P = 1 * 1 * 0.1677
P (A=0) = 0.1677
So, the probability that at any given time none of the weaving machines will be broken down is 0.1677.