Answer:
pvalue = 0.4286 > 0.01, so this information does not suggest that the storm is (perhaps temporarily) increasing above the severe rating
Explanation:
The null hypothesis is:
The alternate hypotesis is:
Our test statistic is:
In which X is the statistic,
is the mean,
is the standard deviation and n is the size of the sample.
In this problem, we have that:
So
Looking at the z-table, z = t = 0.18 has a pvalue of 0.5714.
The alternate hypothesis is accepted if there is a lower than 1%(Because of α = 0.01) probability of finding a value higher than X.
In this problem, X = 16.5, with a pvalue of 0.5714.
1 - 0.5714 = 0.4286 > 0.01
So this information does not suggest that the storm is (perhaps temporarily) increasing above the severe rating