Question

How many moles of S are in 22.4 g of C6H10S

Answer 1

To find the number of moles of S (sulfur) in 22.4 g of C6H10S, divide the mass of the compound by its molar mass. The molar mass of C6H10S can be calculated by summing the atomic masses of each element in the compound.

Step-by-step explanation:

To find the number of moles of S (sulfur) in 22.4 g of C6H10S, we need to use the molar mass of C6H10S. The molar mass of C6H10S is calculated by summing the atomic masses of each element in the compound. Using the periodic table, we find that the molar mass of C is 12.01 g/mol, H is 1.01 g/mol, and S is 32.07 g/mol. Therefore, the molar mass of C6H10S is (6 * 12.01) + (12 * 1.01) + 32.07 = 102.17 g/mol.

To calculate the number of moles, we use the formula:

Moles = Mass / Molar mass

Plugging in the given mass (22.4 g) and the molar mass (102.17 g/mol) into the formula:

Moles = 22.4 g / 102.17 g/mol = 0.219 mol

Therefore, there are 0.219 moles of S in 22.4 g of C6H10S.

Answer 2

Hey there!

Get molar mass of C₆H₁₀S:

C: 6 x 12.01

H: 10 x 1.008

S: 1 x 32.065

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144.205 g

To find the amount of moles we have, divide 22.4 by 144.205. Get 0.155.

There are 0.155 moles of S.

Hope this helps!