Question

The electric force between two charged particles is 0.18 newtons. If the

distance between them is increased by a factor of 3.0, what will the new
electric force be?
0
0.36 newtons
0.02 newtons
0
0.06 newtons
1.62 newtons

Answer 1

Force between two charges is 0.02 N when distance is increased by factor of 3

Step-by-step explanation:

As we know that the two charges will attract or repel each other when they are placed near to each other

Here we know that electrostatic force is given as

`F = (kq_1 q_2)/(r^2)`

here we know that two charges exert 0.18 N force on each other when they are placed at distance "r" from each other

Now when same charges are placed distance "3r" then we have

`F' = (kq_1q_2)/((3r)^2)`

so we have

`F' = (F)/(9)`

`F' = (0.18)/(9)`

`F' = 0.02 N`