96.9k views
1 vote
Please help:
In ΔFTP, sin T=29, sin P=110, and t=9. Find the length of P.

User Pepero
by
6.9k points

2 Answers

3 votes

Answer:

17.4

Explanation:

9/sin(29) = p/sin(110)

p = sin(110) × 9/sin(29)

p = 17.44444259

User Dshap
by
7.0k points
1 vote

Answer:

The length of P is 34.14

Explanation:

Using the sine law

a/sin A = b/sin B

From the question; In ΔFTP, sin T=29, sin P=110, and t=9. Find the length of P.

a = the length of P

Sin A =Sin P = 110

b = t = 9

Sin B = sin T = 29

p/sin P= t/sin T

p/110 = 9/29

Cross multiply

29 x P = 9 ×110

29P = 990

P = 990/29 = 34.13793103= 34.14

User Saurav Nagpal
by
7.8k points