Question

A 9.00-cm-long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wire and rail is 0.320 Ω . Pulling the wire at a steady speed of 4.00 m/s causes 4.30 W of power to be dissipated in the circuit.

Answer 1

0.45 N

Step-by-step explanation:

Let Recall that,

The power formula is:

P = E²/R

Let A = the magnetic field

Let L = length of wire = 9.00cm = 0.09 m

let R = resistance of wire = 0.320 Ω

let v = velocity of the wire = 4 m/s

Let E = across the wire voltage

Let P = the power of the wire = 4.3 W

To Solve for E:

The formula of E = √PR

The Voltage from a magnetic field is given as,

E = vAL

We therefore Use E = E

√PR = vAL

to solve for A,

A= √PR/vL

BA= √4.3(0.32)/(4)(.09) -=0.173

A = 0.173 wA/m²

Let F be the pulling force

Let I be the current in the wire

P = I²R

I = √P/R

F = IAL

F = √P/RAL

F = √4.3/.32(0.173)(.09)

F = 0.45N