Question

The joule (J) is a unit of energy. Recall that energy may be converted between many different forms such as mechanical energy, thermal energy (heat), chemical energy, electrical energy, and light.The mechanical energy produced by a system is called work. When work is accomplished through the changing volume of a gas, it is called PV work and is given by the formula w=−PΔV, where w is the work, P is the external pressure, and ΔV is the change in volume. If the volume change and pressure are in liters and atmospheres respectively, then the work will have units of liter-atmospheres, which can be converted to joules using the conversion factor 1 L⋅atm=101.3 J.Work can also be expressed as force multiplied by distance: w=F×d, where w is the work in joules, F is the force in newtons, and d is the distance in meters. Note that 1 N⋅m=1 J.

Answer 1

Workdone = -1.75 L.atm = -177.275 J

Step-by-step explanation:

Given,

External pressure = 5.00 atm

Initial volume = V(initial) = 0.160 L

Final volume = V(final) = 0.510 L

The piston acts against the constant external pressure of 5.00 atmospheres. The volume expands to 0.510 L from 0.160 L

W = -PΔV

P = 5.00 atm

ΔV = V(final) - V(initial) = 0.510 - 0.160 = 0.35 L

W = - 5 × 0.35 = - 1.75 L.atm

This work can then be expressed in Joules

1 L.atm = 101.3 J

-1.75 L.atm = -1.75 × 101.3 = -177.275 J

Note that the workdone is negative because the system does work on the environment in this expansion procase that led to increase in volume.

Hope this Helps!!!

Answer 2

Complete Question

The complete question is shown on the first uploaded image

Answer:

The workdone is
`W = -177.275J`

Step-by-step explanation:

From the question we are told that

The initial Volume is
`Vi = 0.160 L`

The final volume is
`V_f = 0.510L`

The external pressure is
`P = 5.00 \ atm`

Generally the change in volume is

`\Delta V = V_f - V_i`

Substituting values we have

`\Delta V = 0.510 -0.160`

`= 0.350L`

Generally workdone is mathematically represented as

`W = -P \Delta V`

W is negative because the working is done on the environment by the system which is indicated by volume increase

Substituting values

`W = - 5* 0.350`

`= -1.75 \ L \ \cdot atm`

Now
`1 \ L \cdot atm = 101.3J`

Therefore
`W = -1.75* 101.3`

`= -177.275J`