Question

0.47 moles MgCO3 to g.

450.2 g LiNO3 to moles

36.8g Br2 to molecules

Answer 1

- 39.6 g of MgCO₃

- 6.53 moles of LiNO₃

- 1.38×10²³ molecules of Br₂

Step-by-step explanation:

Let's make some conversions here:

- 0.47 moles of MgCO₃ to g.

We should know, the molar mass of carbonate: 84.3 g /mol

0.47 mol . 84.3 g / 1mol = 39.6 g

- 450.2 g of LiNO₃

Molar mass of nitrate: 68.94 g/mol

450.2 g . 1 mol /68.94g = 6.53 moles of LiNO₃

- Molar mass for dyatomic bromine: 159.80 g/mol

36.8 g . 1 mol/159.80 g = 0.230 moles

1 mol has 6.02×10²³ molecules

0.230 mol . 6.02×10²³ molecules / 1 mol = 1.38×10²³ molecules of Br₂