Answer:
13.61
Step-by-step explanation:
First, we will calculate the molar concentration of NaOH in the final solution.
M = mass NaOH / molar mass NaOH × liters of solution
M = 8.2 g / 40.00 g/mol × 0.500 L
M = 0.41 M
NaOH is a strong base that dissociates according to the following balanced equation.
NaOH → Na⁺ + OH⁻
Then, the concentration of OH⁻ is also 0.41 M.
The pOH is:
pOH = -log [OH⁻]
pOH = -log 0.41 = 0.39
The pH is:
pH + pOH = 14
pH = 14 - pOH = 14 - 0.39 = 13.61