Question

3.247 * 10^17 ions Mg2+ to moles

0.935 mol NH3 to molecules.

Answer 1

- 5.39×10⁻⁷ moles of Mg²⁺ ions

- 5.63×10²³ molecules of NH₃

Step-by-step explanation:

We start from a statement that says:

1 mol of anything contains 6.02×10²³ particles

- Therefore we can say that 1 mol of Mg²⁺ ions has 6.02×10²³ Mg²⁺ ions.

3.247×10¹⁷ ions . 1 mol / 6.02×10²³ ions = 5.39×10⁻⁷ moles of Mg²⁺ ions

- 1 mol of ammonia contains 6.02×10²³ molecules

Therefore 0.935 moles of ammonia will contain (0.935 . 6.02×10²³ ) / 1 =

5.63×10²³ molecules of NH₃