Step-by-step explanation:
First list the givens: (lets name the objects 1 and 2)
BEFORE COLLISION
1:
mass = 2kg
velocity = 3 m/s
Positive direction = ---> (moves to the right)
2:
mass = 3kg
velocity = -2 m/s
Negative direction = <------ (moves to the left)
AFTER COLLISION:
Since they bounce off each other, this is an elastic collision.
1:
mass = 2kg
velocity = -3 m/s
Negative direction <----- (moves to the left)
2:
mass = 3kg
velocity = ?
Positive direction -----> (moves to the right)
BEFORE COLLISION:
(1) -----> <------(2)
AFTER COLLISION:
(1) <------- --------> (2)
Formula to find the velocity of 2 after the collision:
m1v1 + m2v2 = m1v1 + m2v2
(2kg)(3m/s) + (3kg)(-2m/s) = (2kg)(-3m/s) + (3kg)v2
6kgm/s + -6kgm/s = -6kgm/s + 3kgv2
0 = -6 + 3kgv2
Add 6 to the other side
6 = 3kgv2
Divide 3 to the other side
6/3 = 2
v2 = 2
ANSWER:
The velocity to the 3kg mass is 2 m/s