Answer:
0.0252mol/L
Step-by-step explanation:
The following data were obtained obtained from the question:
Volume of solution = 284mL = 284/1000 = 0.284L
Mole of CuSO4 = 7.157 × 10^-3 mol
Molarity =?
Molarity = mole/Volume
Molarity = 7.157x10^-3 /0.284
Molarity = 0.0252mol/L
The concentration of the solution is 0.0252mol/L