Question

If the length of a rectangle in terms of x is 9x² + 5x + 2 and its width is 6x + 1, what is the perimeter of the rectangle?

Answer 1

18x^2 + 22x + 4 -----i dont know for sure if this is correct but i tried my best so dont complain pls if its not correct

Explanation:

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I I ----srry this helps me

I I

I I 9x^2 + 5x + 2

I I

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6x + 1

So you times both by 2 by doing first:

2(6x+1) = 12x + 2

and

2(9x^2 + 5x + 2) = 18x^2 + 10x + 2

Then you need to find the like terms. To find the like terms you need to find two similar terms and add or minus. For example:

2x + 4 - 3x + 2

The two similar terms are: [2x] + 4 [-3x] + 2

so minus them 2x - 3x = -1x and then

4 + 2 = 6 so the final equation is -

6 - 1x . you cant find the like terms of that because they arent the same terms. The same can be said with 2x and 2x^2. Theyre not the same terms.

So continuing with the initial question,

find the like terms of:

18x^2 [+ 10x] (+ 2) [+ 12x] (+ 2) ----- the brackets are just so you know which are like terms.

so the final equation is:

18x^2 + 22x + 4.