Question

helium-filled balloon at sea level has a volume of 2.1 L at 0.998 atm and 36°C. If it is released and rises to an elevation at which the pressure is 0.900 atm and the temperature is 28°C, what will be the new volume of the balloo

Answer 1

the new volume of the balloon would be 2.3 L

Answer 2

2.3L

Step-by-step explanation:

The formula for this problem is p1v1/t1 = p2v2/t2

p1 is .998 atm

v1 is 2.1 L

t1 is 22°C (X°C + 273 = K)

p2 is .900 atm

v2 is x

t2 is 28°C

Solving the problem...

(.998)(2.1)/36+273 = (.900)(x)/28+273

2.0958/309 = .9x/201

x= 2.3