Question

For the reaction NH4NO3 (s) → N2O (g) + 2H2O (l), you decompose 1 mole NH4NO3 and only get 0.75 moles of N2O. The percent yield is 25%.

True or False?

Answer 1

The answer to your question is False.

Step-by-step explanation:

Data

1 mole of NH₄NO₃

0.75 moles of N₂O

Percent yield = 25%

Chemical reaction

NH₄NO₃ ⇒ N₂O + 2H₂O

Process

1.- Determine the theoretical yield

1 mol NH₄NO₃ ------------- 1 mol of N₂O

2.- Calculate the percent yield

Percent yield = Actual yield / Theoretical yield x 100

-Substitution

Percent yield = 0.75 / 1 x 100

-Simplification

Percent yield = 0.75 x 100

-Result

Percent yield = 75%

Conclusion

False, the actual percent yield is 75%