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A rectangle has a height of 4w^3 and a width of 5w^2-3w-4 what is the area

1 Answer

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Final answer:

The area of a rectangle with a height of 4w^3 and a width of
5w^2-3w-4is given by the polynomial
20w^5 - 12w^4 - 16w^3.

Step-by-step explanation:

To find the area of a rectangle, multiply the height by the width. Given a rectangle with a height of
4w^3 and width of
5w^2-3w-4, the area is calculated as:

Area = Height × Width =
(4w^3) X (5w^2 - 3w - 4)

To compute the area, you need to perform the multiplication of these two polynomials:

Area =
4w^3 X 5w^2 - 4w^3 X 3w - 4w^3 X 4

Area =
20w^5 - 12w^4 - 16w^3

The area of the rectangle is
20w^5 - 12w^4 - 16w^3, which is a polynomial expression in terms of w.

User Prakash H
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