Answer:
0.132651
Explanation:
for any 3 passes and any 3 fails the probability is: 0.85×0.85×0.85×0.15×0.15×0.15=0.0020726719
number of free throws: 6
number of possible variations and orders of scoring: 2⁶=64
probably for 3 on 6 is 0.0020726719×64=0.132651